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The length of a rectangle is increased by 20% and its breadth is decreased by 10%. What is the percentage change in its area?рдПрдХ рдЖрдпрдд рдХреА рд▓рдВрдмрд╛рдИ рдореЗрдВ 20% рдХреА рд╡реГрджреНрдзрд┐ рдХреА рдЬрд╛рддреА рд╣реИ рдФрд░ рдЙрд╕рдХреА рдЪреМрдбрд╝рд╛рдИ рдореЗрдВ 10% рдХреА рдХрдореА рдХреА рдЬрд╛рддреА рд╣реИред рдЗрд╕рдХреЗ рдХреНрд╖реЗрддреНрд░рдлрд▓ рдореЗрдВ рдкреНрд░рддрд┐рд╢рдд рдкрд░рд┐рд╡рд░реНрддрди рдХреНрдпрд╛ рд╣реИ?

  • A
    8% increase
    8% рд╡реГрджреНрдзрд┐
  • B
    10% increase
    10% рд╡реГрджреНрдзрд┐
  • C
    8% decrease
    8% рдХрдореА
  • D
    No change
    рдХреЛрдИ рдкрд░рд┐рд╡рд░реНрддрди рдирд╣реАрдВ
Explanation:
Net % change = x + y + (xy/100) = 20 - 10 - (200/100) = 10 - 2 = 8% (positive means increase).
рдиреЗрдЯ рдкреНрд░рддрд┐рд╢рдд рдкрд░рд┐рд╡рд░реНрддрди = 20 - 10 - (200/100) = +8% (рдпрд╛рдиреА 8% рдХреА рд╡реГрджреНрдзрд┐)ред

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This question belongs to the set "Reasoning & General Studies Practice Test #1 for VDO, Patwari, Lekhpal". Click below to read detailed notes and attempt the full quiz.

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