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### Mathematics Practice MCQs

Question 1 of 39

**Q.1 What is the formula for calculating simple interest? **

- SI = (P x R x T) / 100
- SI = (P x R) / T
- SI = (P + R + T) / 100
- SI = (R x T) / P

**Answer ✔ (a) SI = (P x R x T) / 100**

**The correct formula for simple interest is (P x R x T) / 100**

__Explanation:__Question 2 of 39

**Q.2 What does 'P' represent in the simple interest formula? **

- Rate of interest
- Time period
- Principal amount
- Final amount

**Answer ✔ (c) Principal amount**

**'P' stands for the principal amount in the simple interest formula**

__Explanation:__Question 3 of 39

**Q.3 If the principal is ₹1,000, the rate of interest is 5% per annum, and the time is 2 years, what is the simple interest? **

- ₹100
- ₹200
- ₹300
- ₹400

**Answer ✔ (b) ₹200**

**Simple interest is calculated using SI = (P x R x T) / 100**

__Explanation:__Question 4 of 39

**Q.4 Compound interest is calculated on: **

- Principal only
- Principal and accrued interest
- Rate of interest
- Time period only

**Answer ✔ (b) Principal and accrued interest**

**Compound interest is calculated on both principal and accrued interest**

__Explanation:__Question 5 of 39

**Q.5 What is the formula for calculating compound interest annually? **

- A = P(1 + R/100)^T
- A = P + (R x T) / 100
- A = P x R x T
- A = P x T x (R / 100)

**Answer ✔ (a) A = P(1 + R/100)^T**

**Compound interest formula is A = P(1 + R/100)^T**

__Explanation:__Question 6 of 39

**Q.6 If a sum of ₹2,000 is invested at an interest rate of 6% per annum compounded annually for 3 years, what will be the amount after 3 years? **

- ₹2,120
- ₹2,382.03
- ₹2,000
- ₹2,500

**Answer ✔ (b) ₹2,382.03**

**The final amount is calculated using the compound interest formula A = P(1 + R/100)^T**

__Explanation:__Question 7 of 39

**Q.7 The difference between simple interest and compound interest on ₹5,000 for 2 years at a rate of 5% per annum is: **

- ₹6.25
- ₹12.50
- ₹25
- ₹50

**Answer ✔ (b) ₹12.50**

**The difference is ₹12.50 due to the compound effect over 2 years**

__Explanation:__Question 8 of 39

**Q.8 If the interest is compounded half-yearly, how many times per year is the interest compounded? **

- 1
- 2
- 3
- 4

**Answer ✔ (b) 2**

**Half-yearly compounding means the interest is compounded twice a year**

__Explanation:__Question 9 of 39

**Q.9 In compound interest, if the interest is compounded quarterly, the number of compounding periods in a year is: **

- 1
- 2
- 3
- 4

**Answer ✔ (d) 4**

**Quarterly compounding means the interest is compounded 4 times a year**

__Explanation:__Question 10 of 39

**Q.10 A sum of money becomes ₹6,000 in 2 years and ₹6,600 in 3 years at compound interest. What is the rate of interest? **

- 5%
- 10%
- 15%
- 20%

**Answer ✔ (b) 10%**

**The rate of interest is 10% based on the growth from ₹6,000 to ₹6,600 in one year**

__Explanation:__Question 11 of 39

**Q.11 A sum of ₹8,000 amounts to ₹9,261 in 2 years at compound interest. What is the rate of interest? **

- 5%
- 7.5%
- 10%
- 12.5%

**Answer ✔ (c) 10%**

**The sum increased at a rate of 10% per annum**

__Explanation:__Question 12 of 39

**Q.12 The simple interest on a sum of ₹12,000 at 6% per annum for 4 years is: **

- ₹2,880
- ₹2,400
- ₹3,000
- ₹2,700

**Answer ✔ (a) ₹2,880**

**Simple interest is calculated using the formula SI = (P x R x T) / 100**

__Explanation:__Question 13 of 39

**Q.13 In how many years will a sum of ₹1,000 become ₹1,210 at 10% compound interest per annum? **

- 1 year
- 2 years
- 3 years
- 4 years

**Answer ✔ (b) 2 years**

**The sum will amount to ₹1,210 in 2 years at 10% compound interest**

__Explanation:__Question 14 of 39

**Q.14 The difference between compound interest and simple interest on a sum of ₹5,000 for 3 years at 8% per annum is: **

- ₹24
- ₹32
- ₹40
- ₹50

**Answer ✔ (c) ₹40**

**The difference is ₹40 due to compounding**

__Explanation:__Question 15 of 39

**Q.15 What is the compound interest on ₹10,000 at 5% per annum compounded yearly for 2 years? **

- ₹1,000
- ₹1,025
- ₹1,050
- ₹1,100

**Answer ✔ (b) ₹1,025**

**The compound interest after 2 years is ₹1,025**

__Explanation:__Question 16 of 39

**Q.16 At what rate of simple interest will a sum of money double itself in 12 years? **

- 8.33%
- 10%
- 12%
- 14%

**Answer ✔ (b) 10%**

**The rate of interest should be 8.33% for the sum to double in 12 years**

__Explanation:__Question 17 of 39

**Q.17 If ₹6,000 becomes ₹7,200 in 2 years at simple interest, what is the rate of interest? **

- 10%
- 12%
- 15%
- 20%

**Answer ✔ (b) 12%**

**The rate of interest is 10% using SI = (P x R x T) / 100**

__Explanation:__Question 18 of 39

**Q.18 At what rate will ₹10,000 amount to ₹11,000 in 2 years at compound interest? **

- 4.88%
- 5%
- 9.53%
- 10%

**Answer ✔ (a) 4.88%**

**The rate is approximately 4.88%, calculated using the compound interest formula**

__Explanation:__Question 19 of 39

**Q.19 The simple interest on ₹5,000 at 8% per annum for 3 years is: **

- ₹1,200
- ₹1,000
- ₹1,400
- ₹1,600

**Answer ✔ (a) ₹1,200**

**The simple interest is calculated as ₹1,200**

__Explanation:__Question 20 of 39

**Q.20 The compound interest on ₹4,000 for 2 years at 5% per annum compounded annually is: **

- ₹410
- ₹400
- ₹420
- ₹450

**Answer ✔ (a) ₹410**

**The compound interest is ₹410 calculated using the compound interest formula**

__Explanation:__Question 21 of 39

**Q.1 14 persons can complete a work in 16 days, 8 persons started the work 12 days after they started the work, 8 more peoples joined them. How many days will they take to complete the remaining work **

- 12
- 8
- 9
- 5

**Answer ✔ (b) 8**

**14 persons complete in 16days = 1 work, =>8 persons complete in 12 days = (1x8)/14 x 12/16 = 3/7 , =>remaining work = 1- 3/7 = 4/7 and total no. of persons = 8+8 , 14 persons do 1 work in =16 day, 16 persons do 4/7 work in = 16 x14 /16 x 4/7 = 8 days Ans.**

__Explanation:__Question 22 of 39

**Q.2 A train running at 90 km/hr crosses a pole in 10 seconds. What is the length of train? **

- 250 m
- 150 m
- 900 m
- none of these

**Answer ✔ (a) 250 m**

**speed of train = Length of train / time taken to cross**

__Explanation:__Question 23 of 39

**Q.3 When a 192 meter long rod is cut down into small pieces of length 3.2 meter each. Then how many pieces are available? **

- 52
- 68
- 60
- 58

**Answer ✔ (c) 60**

**required no. of pieces = 192/3.2 = 60**

__Explanation:__Question 24 of 39

**Q.4 The ratio between the present age of Sudhir and Madan is 4:5 , if after five years the ratio of their age becomes 5 : 6, what is the present age of Sudhir? **

- 18 years
- 20 years
- 22 years
- 21 years

**Answer ✔ (b) 20 years**

Question 25 of 39

**Q.5 The sum of three consecutive odd numbers is 20 more than the first number of these. What is the middle number? **

- 7
- 8
- 12
- 9

**Answer ✔ (d) 9**

Question 26 of 39

**Q.6 If one-third of a number is 10 more than one fourth of the same number, what is 60% of that number? **

- 144
- 24
- 18
- 72

**Answer ✔ (d) 72**

Question 27 of 39

**Q.7 If the length and breadth of a rectangular plot are increased by 50% and 20% respectively, how many times will be the new area of the old area? **

- 1 and 4/5
- 2
- 3 and 2/5
- 5 and 1/5

**Answer ✔ (a) 1 and 4/5**

Question 28 of 39

**Q.8 A rectangular plot is 50m long and 20 m broad. Inside it there is a path of 7 m wide all round it. What is the area of the path? **

- 216 sq. m
- 1000 sq.m
- 1216 sq. m
- 784 sq. m

**Answer ✔ (d) 784 sq. m**

Question 29 of 39

**Q.9 Find the compound interest of Rs. 10,000 in 9 months at 4% per annum interest payable quarterly. **

- Rs. 300
- Rs. 310
- Rs 303
- Rs 303.01

**Answer ✔ (d) Rs 303.01**

Question 30 of 39

**Q.10 Find out the ratio whose value is 2/3 and the antecedent is 18 **

- 18:27
- 02:03
- 20:30
- 180:270

**Answer ✔ (a) 18:27**

**The two quantties compared in a ratio is called its items. The first term is called antecedent, the second the consequent.**

__Explanation:__Question 31 of 39

**Q.1 If 3 men and 4 boys complete a work in 7 days and 2 men and 3 boys do the same work in 10 days . In **

- 5 days
- 3 days
- 7 days
- 6 days

**Answer ✔ (a) 5 days**

__Explanation:__Question 32 of 39

**Q.1 In an election between two candidates 10% voters doesn’t cast their votes and 85 votes were de **

- 400
- 600
- 800
- 1000

**Answer ✔ (c) 800**

**Lets take total votes =100% 10%doesn’t cast their votes So, (100-90) = 90% cast their votes. total valid votes = 90% -85 one candidate get 50% of votes of voters list. So, other candidate get = (90% - 85 )-50%= 40% - 85 so ,50 % - (40% - 85) = 165 50% - 40% + 85 = 165 10% = 80 100 % = 800 So total voters is 800**

__Explanation:__Question 33 of 39

**Q.1 A Trader Who Marks His Good Upto 50% And Offered Discount Of 20% . What % Profit The Trade Makes After Offering The Payment? **

- 15%
- 20%
- 25%
- 40%

**Answer ✔ (b) 20%**

**Sol. Let cp = 100, MRP = 150**

__Explanation:__\( sp = 150 \times {80 \over 100} \)

\( = Rs. 120 \)

Hence, Profit = 20%

[short trick:]

By successive formula

\( x+y+{xy \over 100} \)

\( 50-20+{50 \times (-20) \over 100} \)

30 – 10 = 20%

Question 34 of 39

**Q.1 What number has 5 to 1 ratio to the number 10? **

- 42
- 55
- 50
- 60

**Answer ✔ (c) 50**

**Given, ratio is 5 : 1 that means antecedent is 5 times greater than the consequent.**

__Explanation:__Given consequent = 10, so the number is 10 × 5 = 50 answer.

Question 35 of 39

**Q.2 There are 120 students in a picnic tour, if ratio of girls and boys is 5 : 7 then how many boys are in this tour? **

- 50
- 70
- 55
- 120

**Answer ✔ (b) 70**

**Given ratio of girls : boys = 5 : 7 = 5/7**

__Explanation:__multiplying the antecedent and consequent by the same number, let by

*x,*

girls = 5

*x*, and boys = 7

*x*

total = 120;

as par given 5x + 7x = 120

=> x = 120/12 = 10

hence, girls = 5 × 10 = 50

and Boys = 7 × 10 =

**70**answer

Question 36 of 39

**Q.3 in 3 : 5 , here 3 is **

- antecedent
- consequent
- means
- extremes

**Answer ✔ (a) antecedent**

**in a ratio the first term is called antecedent and the second term is called consequent. in 3 : 5, 3 is antecedent and 5 is consequent, means and extremes are terms used in case of proportion**

__Explanation:__i.e. 1 : 2 :: 2 : 4, here 1 and 4 are extremes and 2 and 2 are means.

Question 37 of 39

**Q.1 The average weight of A, B and C is 45 kg, that of A and B is 40 kg and B and C is 43 kg. What is the weight of B? **

- 17 kg
- 26 kg
- 20 kg
- 31 kg

**Answer ✔ (d) 31 kg**

**Weight of A+B+C = 45 × 3 = 135 kg .....(i)**

__Explanation:__Wt. Of A+B = 40 × 2 = 80 kg .....(ii)

Weight of B + C = 43 × 2 = 86 kg ......

(iii)

Now on adding (ii) and (iii),

wt. of A+2B+C = 166kg

A+B+ C = 135 kg ....given (i)

On Subtracting (i)

B = 31 kg ..Ans

Question 38 of 39

**Q.2 The average of following 5 numbers is 8, find the missing number in 7, 5, 3,12,?. **

- 14
- 13
- 8
- 12

**Answer ✔ (b) 13**

**The sum of all numbers = 8 × 5 = 40**

__Explanation:__So, ? = 40 - (7+3+12+5) = 13 Ans.

Question 39 of 39

**Q.3 The average of the first three numbers is double of the fourth number. if the average of all the four numbers is 12, find the 4th number. **

- 16
- 20
- 18
- 48/7

**Answer ✔ (d) 48/7**

**Let the 4th number be x,**

__Explanation:__Then the average of first three numbers = 2x ,

So the sum of first 3 numbers = 2x × 3 = 6x,

Since the average of 4 numbers = 12.

Then sum of 4 numbers = 12 × 4 = 48.

so, 48 - 6x = x => 7x = 48,

x = 48/7 ..Ans.